(C) Given that $x - 1$ is a factor of $p(x) = kx^2 - 3x + k$.According to the Factor Theorem,if $(x - a)$ is a factor of $p(x)$,then $p(a) = 0$.Here,$

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(C) Given that $x - 1$ is a factor of $p(x) = kx^2 - 3x + k$.According to the Factor Theorem,if $(x - a)$ is a factor of $p(x)$,then $p(a) = 0$.Here,$a = 1$,so $p(1) = 0$.Substituting $x = 1$ into the polynomial:$p(1) = k(1)^2 - 3(1) + k = 0$$k - 3 + k = 0$$2k - 3 = 0$$2k = 3$$k = 3/2$.