Find the value of $(625)^{-\frac{3}{4}}$.
- A$1/125$
- B$1/25$
- C$125$
- D$25$
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Find:
$(i)$ $2^{2/3} \cdot 2^{1/5}$
$(ii)$ $(1/3^3)^7$
$(iii)$ $11^{1/2} / 11^{1/4}$
$(iv)$ $7^{1/2} \cdot 8^{1/2}$
$(i)$ $2^{2/3} \cdot 2^{1/5}$
$(ii)$ $(1/3^3)^7$
$(iii)$ $11^{1/2} / 11^{1/4}$
$(iv)$ $7^{1/2} \cdot 8^{1/2}$
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View Solution$\sqrt[4]{\sqrt[3]{2^{2}}}$ equals
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View SolutionFind the value of $\frac{8^{1/3} \times 16^{1/3}}{32^{-1/3}}$.
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View SolutionFind:
$(i)$ $9^{\frac{3}{2}}$
$(ii)$ $32^{\frac{2}{5}}$
$(iii)$ $16^{\frac{3}{4}}$
$(iv)$ $125^{-\frac{1}{3}}$
$(i)$ $9^{\frac{3}{2}}$
$(ii)$ $32^{\frac{2}{5}}$
$(iii)$ $16^{\frac{3}{4}}$
$(iv)$ $125^{-\frac{1}{3}}$
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