Find the total number of electrons,protons,an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Calculate the number of moles of $_{16}^{32}S$: $	ext{Moles} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{0.192 \ g}{32 \ g/mol} = 0.006

Vedclass · Accepted Answer

$1.734 	imes 10^{23}$

Vedclass · Answer

(B) $1$. Calculate the number of moles of $_{16}^{32}S$: $	ext{Moles} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{0.192 \ g}{32 \ g/mol} = 0.006 \ mol$. $2$. Calculate the number of atoms: $	ext{Atoms} = 0.006 	imes 6.022 	imes 10^{23} = 3.6132 	imes 10^{21} 	ext{ atoms}$. $3$. For $_{16}^{32}S$,the number of protons = $16$,electrons = $16$,and neutrons = $32 - 16 = 16$. $4$. Total subatomic particles per atom = $16 + 16 + 16 = 48$. $5$. Total number of particles = $3.6132 	imes 10^{21} 	imes 48 = 1.734 	imes 10^{23}$.

Find the total number of electrons,protons,and neutrons in $0.192 \ g$ of $_{16}^{32}S$.

Similar Questions

The number of electrons in $2.1 \ g$-ion of $Cl^{-}$ is

How many molecules are present in one gram of hydrogen? (Value $\times 10^{23}$)

What is the weight of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$ in grams?

The number of water molecules present in a drop of water (volume $0.0018 \ mL$) at room temperature is

What is the total number of neutrons present in $1.7 \ g$ of ammonia $(NH_3)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module