Five elements A, B, C, D and E have work func | vedclass

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(C) The energy of an incident photon is given by the formula $E = \frac{hc}{\lambda}$.Using the approximation $hc \approx 12400 \ eV \cdot \mathring{A

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$A$ and $B$

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(C) The energy of an incident photon is given by the formula $E = \frac{hc}{\lambda}$.Using the approximation $hc \approx 12400 \ eV \cdot \mathring{A}$,we get:$E = \frac{12400 \ eV \cdot \mathring{A}}{4000 \ \mathring{A}} = 3.1 \ eV$.Photoelectric emission occurs only if the energy of the incident photon is greater than or equal to the work function $(\Phi)$ of the material.Comparing the incident energy $(3.1 \ eV)$ with the given work functions:For $A$ $(1.2 \ eV)$: $3.1 \ eV > 1.2 \ eV$ (Emission occurs)For $B$ $(2.4 \ eV)$: $3.1 \ eV > 2.4 \ eV$ (Emission occurs)For $C$ $(3.6 \ eV)$: $3.1 \ eV For $D$ $(4.8 \ eV)$: $3.1 \ eV For $E$ $(6 \ eV)$: $3.1 \ eV Therefore,photoelectrons are emitted only by elements $A$ and $B$.

Five elements $A, B, C, D$ and $E$ have work functions $1.2 \ eV, 2.4 \ eV, 3.6 \ eV, 4.8 \ eV$ and $6 \ eV$ respectively. If light of wavelength $4000 \ \mathring{A}$ is allowed to fall on these elements,then photoelectrons are emitted by:

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