Five moles of helium are mixed with two moles | vedclass

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(A) Helium $(He)$ is a monoatomic gas,so its degree of freedom $f_1 = 3$. The number of moles $n_1 = 5$.Hydrogen $(H_2)$ is a diatomic gas,so its degr

Vedclass · Accepted Answer

$3.57$

Vedclass · Answer

(A) Helium $(He)$ is a monoatomic gas,so its degree of freedom $f_1 = 3$. The number of moles $n_1 = 5$.Hydrogen $(H_2)$ is a diatomic gas,so its degree of freedom $f_2 = 5$. The number of moles $n_2 = 2$.The equivalent degree of freedom $f_{mix}$ for a mixture of gases is given by the formula:$f_{mix} = \frac{n_1 f_1 + n_2 f_2}{n_1 + n_2}$Substituting the values:$f_{mix} = \frac{(5 	imes 3) + (2 	imes 5)}{5 + 2}$$f_{mix} = \frac{15 + 10}{7}$$f_{mix} = \frac{25}{7} \approx 3.57$Thus,the correct option is $A$.

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium $M_1=4 \ g$ and that of hydrogen $M_2=2 \ g$. The equivalent degree of freedom $f$ of the mixture is:

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