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(D) For a solution to have $pH = 1$,the concentration of $[H^+]$ must be $10^{-1} \; M = 0.1 \; M$.Let us calculate the final $[H^+]$ for each case:$a

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$c$

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(D) For a solution to have $pH = 1$,the concentration of $[H^+]$ must be $10^{-1} \; M = 0.1 \; M$.Let us calculate the final $[H^+]$ for each case:$a. \; [H^+] = \frac{(60 	imes 0.1) - (40 	imes 0.1)}{60 + 40} = \frac{6 - 4}{100} = 0.02 \; M \; (pH \approx 1.7)$$b. \; [H^+] = \frac{(55 	imes 0.1) - (45 	imes 0.1)}{55 + 45} = \frac{5.5 - 4.5}{100} = 0.01 \; M \; (pH = 2)$$c. \; [H^+] = \frac{(75 	imes 0.2) - (25 	imes 0.2)}{75 + 25} = \frac{15 - 5}{100} = \frac{10}{100} = 0.1 \; M \; (pH = 1)$$d. \; [H^+] = 0 \; M \; (pH = 7, 	ext{neutral solution})$Thus,the solution $c$ has $pH = 1$.

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