Foot of a 10,m long ladder leaning against a | vedclass

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Question

(C) Let $AB$ be the vertical wall and $AC = 10\,m$ be the length of the ladder.The distance of the foot of the ladder from the base of the wall is $BC

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) Let $AB$ be the vertical wall and $AC = 10\,m$ be the length of the ladder.The distance of the foot of the ladder from the base of the wall is $BC = 6\,m$.In the right-angled $	riangle ABC$,by the Pythagoras theorem:$AC^2 = AB^2 + BC^2$$(10)^2 = AB^2 + (6)^2$$100 = AB^2 + 36$$AB^2 = 100 - 36 = 64$$AB = \sqrt{64} = 8\,m$.Thus,the height of the point on the wall where the top of the ladder reaches is $8\,m$.

Foot of a $10\,m$ long ladder leaning against a vertical wall is $6\,m$ away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches. (in $m$)

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