For $k=1, 2, 3$, the box $B_k$ contains $k$ red balls and $(k+1)$ white balls. Let $P(B_1)=\frac{1}{2}$, $P(B_2)=\frac{1}{3}$, and $P(B_3)=\frac{1}{6}$. $A$ box is selected at random and a ball is drawn from it. If a red ball is drawn, then the probability that it has come from box $B_2$ is:

  • A
    $\frac{35}{78}$
  • B
    $\frac{14}{39}$
  • C
    $\frac{10}{13}$
  • D
    $\frac{12}{13}$

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