For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

For a common emitter transistor,the current gain is $50$,the input resistance is $1 \ k\Omega$,and the input voltage is $0.01 \ V$. What is the collector current?

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relation between $\alpha$ and $\beta$ is

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter in $10^{-6} \ s$ and $2\%$ of the electrons recombine with holes in the base. The current gains $\alpha$ and $\beta$ are respectively:

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.

When a signal is applied to the input of a transistor,it is found that the output signal is phase-shifted by $180^{\circ}$. The transistor configuration is: