For a continuous series,the mode is computed | vedclass

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Question

(C) The formula for calculating the mode for a continuous frequency distribution is given by: $Mode = l + \left( \frac{f_m - f_{m-1}}{2f_m - f_{m-1} -

Vedclass · Accepted Answer

$l + \frac{f_m - f_{m-1}}{2f_m - f_{m-1} - f_{m+1}} 	imes C$ or $l + \frac{f_m - f_1}{2f_m - f_1 - f_2} 	imes i$

Vedclass · Answer

(C) The formula for calculating the mode for a continuous frequency distribution is given by: $Mode = l + \left( \frac{f_m - f_{m-1}}{2f_m - f_{m-1} - f_{m+1}} ight) 	imes C$ where: $l$ is the lower limit of the modal class,$f_m$ is the frequency of the modal class,$f_{m-1}$ is the frequency of the class preceding the modal class,$f_{m+1}$ is the frequency of the class succeeding the modal class,$C$ (or $i$) is the width of the class interval. Thus,option $C$ is correct.

$x$	$4$	$5$	$6$	$7$	$8$
$f$	$6$	$7$	$10$	$8$	$3$

Class	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$a$	$b$	$12$	$9$	$5$

For a continuous series,the mode is computed by the formula:

Similar Questions

$A$ set of numbers consists of three $4$'s,five $5$'s,six $6$'s,eight $8$'s,and seven $10$'s. The mode of this set of numbers is:

If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

If in a frequency distribution,the mean and median are $21$ and $22$ respectively,then its mode is approximately

Find the mode of the following frequency distribution.

$x$ $4$ $5$ $6$ $7$ $8$

$f$ $6$ $7$ $10$ $8$ $3$

Consider the following frequency distribution:

Class $0-6$ $6-12$ $12-18$ $18-24$ $24-30$

Frequency $a$ $b$ $12$ $9$ $5$

If $\text{mean} = \frac{309}{22}$ and $\text{median} = 14$,then the value of $(a-b)^{2}$ is equal to $.....$

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