For a first order reaction $A \rightarrow P$,the temperature $(T)$ dependent rate constant $(k)$ was found to follow the equation $\log k = -(2000) \frac{1}{T} + 6.0$. The pre-exponential factor $A$ and the activation energy $E_{a}$,respectively,are

  • A
    $1.0 \times 10^6 \ s^{-1}$ and $9.2 \ kJ \ mol^{-1}$
  • B
    $6.0 \ s^{-1}$ and $16.6 \ kJ \ mol^{-1}$
  • C
    $1.0 \times 10^6 \ s^{-1}$ and $16.6 \ kJ \ mol^{-1}$
  • D
    $1.0 \times 10^6 \ s^{-1}$ and $38.3 \ kJ \ mol^{-1}$

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Similar Questions

Define the following terms:
$(1)$ Fraction of molecules
$(2)$ Frequency factor

Consider the following statements:
$(i)$ Increase in concentration of reactant increases the rate of a zero order reaction
$(ii)$ Rate constant $k$ is equal to $A$ if $E_a = 0$
$(iii)$ Rate constant $k$ is equal to $A$ if $E_a = \infty$
$(iv)$ $\log_e k$ vs $T$ is a straight line
$(v)$ $\log_e k$ vs $1/T$ is a straight line
Which of the following statements are correct?

Difficult
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$A$ large increase in the rate of reaction for a small increase in temperature is due to:

For an effective collision to occur,the colliding molecules must possess:

For the following reactions:
$A \xrightarrow{700 \ K}$ Product
$A \xrightarrow[\text{catalyst}]{500 \ K}$ Product
it was found that $E_{a}$ is decreased by $30 \ kJ/mol$ in the presence of a catalyst. If the rate remains unchanged,the activation energy for the catalysed reaction is (Assume pre-exponential factor is same):

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