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(C) Given that the first term $a = 5$ and the $19^{th}$ term $l = T_{19} = 95$.The number of terms $n = 19$.The formula for the sum of $n$ terms of an

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$950$

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(C) Given that the first term $a = 5$ and the $19^{th}$ term $l = T_{19} = 95$.The number of terms $n = 19$.The formula for the sum of $n$ terms of an $A.P.$ when the first and last terms are known is $S_{n} = \frac{n}{2}(a + l)$.Substituting the values: $S_{19} = \frac{19}{2}(5 + 95)$.$S_{19} = \frac{19}{2}(100)$.$S_{19} = 19 	imes 50 = 950$.Therefore,the sum of the $19$ terms is $950$.

For a given $A.P.$,the first term is $5$ and the $19^{th}$ term is $95$. Then,the sum of its $19$ terms is $\ldots \ldots \ldots \ldots$

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