For a rhombus plot,its perimeter is 680 , m a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The perimeter of the rhombus is $680 \, m$. Since all sides of a rhombus are equal,the side length $a = 680 / 4 = 170 \, m$.$2$. Let the diag

Vedclass · Accepted Answer

$24000$

Vedclass · Answer

(D) $1$. The perimeter of the rhombus is $680 \, m$. Since all sides of a rhombus are equal,the side length $a = 680 / 4 = 170 \, m$.$2$. Let the diagonals be $d_1 = 300 \, m$ and $d_2$. In a rhombus,diagonals bisect each other at right angles.$3$. Considering a right-angled triangle formed by the sides of the rhombus and half of the diagonals,we have $(d_1/2)^2 + (d_2/2)^2 = a^2$.$4$. Substituting the values: $(300/2)^2 + (d_2/2)^2 = 170^2$,which gives $150^2 + (d_2/2)^2 = 28900$.$5$. $22500 + (d_2/2)^2 = 28900$,so $(d_2/2)^2 = 6400$,which means $d_2/2 = 80 \, m$.$6$. Thus,$d_2 = 160 \, m$.$7$. The area of the rhombus is $(1/2) 	imes d_1 	imes d_2 = (1/2) 	imes 300 	imes 160 = 24000 \, m^2$.

For a rhombus plot,its perimeter is $680 \, m$ and one of its diagonals is $300 \, m$. Find the area of the plot. (in $, m^2$)

Similar Questions

In quadrilateral $ABCD$,$\angle A : \angle B : \angle C : \angle D = 1 : 4 : 2 : 2$. Find the measure of each angle of the quadrilateral.

In the figure,$AB \parallel DE$,$AB = DE$,$AC \parallel DF$ and $AC = DF$. Prove that $BC \parallel EF$ and $BC = EF$.

Area of a square $= (........... )^{2}.$

The diagonals of a rhombus are $16\,cm$ and $30\,cm$. Find its perimeter. (in $,cm$)

$(1)$ If no three points out of four coplanar points are collinear,then a $\ldots \ldots \ldots$ figure formed by joining these four points in order is called a quadrilateral.
$(2)$ $A$ quadrilateral has $\ldots \ldots \ldots$ pairs of opposite sides.

Vedclass Test Series

Exam Paper Generator

Online Exam Module