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(C) For a rigid diatomic molecule,the degrees of freedom $f = 5$.The molar specific heat at constant volume is $C_V = \frac{f}{2} R = \frac{5}{2} R$.T

Vedclass · Accepted Answer

$0.2857$

Vedclass · Answer

(C) For a rigid diatomic molecule,the degrees of freedom $f = 5$.The molar specific heat at constant volume is $C_V = \frac{f}{2} R = \frac{5}{2} R$.The molar specific heat at constant pressure is $C_P = C_V + R = \frac{5}{2} R + R = \frac{7}{2} R$.We are given the relation $R = n C_P$.Substituting the value of $C_P$,we get $R = n (\frac{7}{2} R)$.Dividing both sides by $R$,we get $1 = n (\frac{7}{2})$.Therefore,$n = \frac{2}{7} \approx 0.2857$.

For a rigid diatomic molecule,the universal gas constant $R = n C_P$,where $C_P$ is the molar specific heat at constant pressure and $n$ is a number. Hence,$n$ is equal to

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