For a telescope,the focal length of the objec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Focal length of objective lens $f_o = 15 \ cm = 150 \ mm$. Focal length of eyepiece $f_e = 10 \ mm = 1 \ cm$. Tube length $L = 16 \ cm$. Fo

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) Given: Focal length of objective lens $f_o = 15 \ cm = 150 \ mm$. Focal length of eyepiece $f_e = 10 \ mm = 1 \ cm$. Tube length $L = 16 \ cm$. For a telescope in normal adjustment,the tube length $L = f_o + f_e$. Here,$f_o + f_e = 15 \ cm + 1 \ cm = 16 \ cm$,which matches the given tube length. Thus,the telescope is in normal adjustment. The magnification $M$ for a telescope in normal adjustment is given by $M = \frac{f_o}{f_e}$. $M = \frac{15 \ cm}{1 \ cm} = 15$. Therefore,the magnification is $15$.

For a telescope,the focal length of the objective lens is $15 \ cm$ and the focal length of the eyepiece is $10 \ mm$. If the tube length is $16 \ cm$,find the magnification.

Similar Questions

Pili or fimbriae are associated with which process?

The product obtained at the anode when $50 \%$ $H_2SO_4$ aqueous solution is electrolysed using platinum electrodes is:

Which logic gate is represented by the following combination of logic gates?

Which carbohydrate is used in the silvering of mirrors?

Which of the following is not produced during the electrolysis of brine solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module