For a transistor in $CE$ mode to be used as an amplifier,it must be operated in:

In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

In an $NPN$ transistor,$10^{10}$ electrons enter the emitter region in $10^{-6} \, s$. If $2 \%$ of electrons are lost in the base region,then the collector current and the current amplification factor $(\beta)$ are,respectively:

When a signal is applied to the input of a transistor,it is found that the output signal is phase-shifted by $180^{\circ}$. The transistor configuration is:

In a transistor, if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$, then the value of $\beta$ lies between:

For a transistor,if the emitter current $I_E = 25 \, mA$ and the base current $I_B = 1 \, mA$,what is the ratio of the collector current $I_C$ to the emitter current $I_E$?