For an electron,if the uncertainty in velocity is $\Delta \nu$,the uncertainty in its position $(\Delta x)$ is given by:

  • A
    $\frac{h}{4\pi m \Delta \nu}$
  • B
    $\frac{4\pi}{hm \Delta \nu}$
  • C
    $\frac{h}{4\pi m \Delta \nu}$
  • D
    $\frac{4\pi m}{h \Delta \nu}$

Explore More

Similar Questions

Given below are two statements:
Statement $I:$ According to Bohr's model of hydrogen atom,the angular momentum of an electron in a given stationary state is quantised.
Statement $II:$ The concept of electron in Bohr's orbit,violates the Heisenberg uncertainty principle.
In the light of the above statements,choose the most appropriate answer from the options given below:

According to Heisenberg's uncertainty principle,the product of uncertainties in position and velocity for an electron of mass $9.1 \times 10^{-31} \ kg$ is

Difficult
View Solution

The uncertainty in the position of an electron is $1 \, \mathring{A}$. Find the uncertainty in its velocity.

The uncertainty in the position of an electron moving with a velocity of $3 \times 10^4 \ cm/s$ is (given mass of electron $= 9.1 \times 10^{-28} \ g$,uncertainty in velocity $= 0.02 \ \%$).

If the uncertainty in position is of the order of $1 \, \mathring{A}$,what will be the uncertainty in velocity of a cricket ball weighing $150 \, g$?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo