For any integer $n \geq 1$,the sum $\sum_{k=1}^n k(k+2)$ is equal to

  • A
    $\frac{n(n+1)(n+2)}{6}$
  • B
    $\frac{n(n+1)(2n+1)}{6}$
  • C
    $\frac{n(n+1)(2n+7)}{6}$
  • D
    $\frac{n(n+1)(2n+9)}{6}$

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