For complete combustion of 10 L of alkane,th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The general combustion reaction for an alkane is:$C_n H_{2n+2} + (\frac{3n+1}{2}) O_2 \rightarrow nCO_2 + (n+1) H_2O$According to Avogadro's Law,t

Vedclass · Accepted Answer

$C_3H_8$

Vedclass · Answer

(B) The general combustion reaction for an alkane is:$C_n H_{2n+2} + (\frac{3n+1}{2}) O_2 ightarrow nCO_2 + (n+1) H_2O$According to Avogadro's Law,the ratio of volumes of gases is equal to the ratio of their stoichiometric coefficients.$\frac{	ext{Volume of Alkane}}{	ext{Volume of } O_2} = \frac{1}{\frac{3n+1}{2}} = \frac{2}{3n+1}$Given that the volume of alkane is $10 \ L$ and the volume of $O_2$ is $50 \ L$:$\frac{10}{50} = \frac{2}{3n+1}$$\frac{1}{5} = \frac{2}{3n+1}$$3n + 1 = 10$$3n = 9$$n = 3$Substituting $n = 3$ into the general formula $C_n H_{2n+2}$,we get $C_3 H_{2(3)+2} = C_3H_8$.

For complete combustion of $10 \ L$ of alkane,the volume of oxygen required is $50 \ L$. Identify the alkane.

Similar Questions

How many monochloro structural isomers are expected to be formed on free radical monochlorination of isopentane?

Assertion $(A):$ Sodium acetate on Kolbe's electrolysis gives ethane.
Reason $(R):$ Methyl free radical is formed at cathode.

How many pairs of enantiomers are formed during the monochlorination of $2$-methylbutane?

Which type of hydrogen atoms are present in $(CH_3)_3CH$?

$CH_4 + Cl_2 \xrightarrow{UV} CH_3Cl + HCl$. This reaction is an example of.........

Vedclass Test Series

Exam Paper Generator

Online Exam Module