For full scale deflection of total $50$ divisions, $50 \, mV$ voltage is required in a galvanometer. The resistance of the galvanometer, if its current sensitivity is $2 \, div/mA$, will be $..... \Omega$.

$A$ moving coil galvanometer is converted into an ammeter, reading up to $0.04 \,A$ by connecting a shunt of resistance '$3r$' across it and then into an ammeter reading up to $0.8 \,A$, when a shunt of resistance '$r$' is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used (in $\,A$)?

$A$ galvanometer having internal resistance $10 \Omega$ requires $0.01 \ A$ for a full scale deflection. To convert this galvanometer to a voltmeter of full-scale deflection at $120 \ V$, we need to connect a resistance of

An ammeter with a resistance of $0.018 \, \Omega$ can measure $1 \, A$. What shunt resistance is required to enable it to measure $10 \, A$?

With a resistance '$X$' connected in series with a galvanometer of resistance $100 \Omega$, it acts as a voltmeter of range $0 - 15 \text{ V}$. To double the range, a resistance of $1500 \Omega$ is to be connected in series with '$X$'. The value of '$X$' in $\Omega$ is

$A$ galvanometer having a resistance of $9 \, \Omega$ is shunted by a wire of resistance $2 \, \Omega$. If the total current is $1 \, A$, the part of it passing through the shunt will be ............ $A$.