For given data N=60, sum X^2=18000 and sum X= | vedclass

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(D) The formula for variance is given by $\sigma^2 = \frac{\sum X^2}{N} - \left(\frac{\sum X}{N}\right)^2$. Given values are $N=60$,$\sum X^2=18000$,a

Vedclass · Accepted Answer

$44$

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(D) The formula for variance is given by $\sigma^2 = \frac{\sum X^2}{N} - \left(\frac{\sum X}{N}\right)^2$. Given values are $N=60$,$\sum X^2=18000$,and $\sum X=960$. Substituting these values into the formula: $\sigma^2 = \frac{18000}{60} - \left(\frac{960}{60}\right)^2$. $\sigma^2 = 300 - (16)^2$. $\sigma^2 = 300 - 256$. $\sigma^2 = 44$. Thus,the variance of the data is $44$.

$C$.$I$.	$0$ - $6$	$6$ - $12$	$12$ - $18$
f_i	$2$	$4$	$6$

For given data $N=60, \sum X^2=18000$ and $\sum X=960$,then variance of data is

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