For a moving cricket ball,which of the following statements regarding the de-Broglie wavelength is correct?

The figure shows four situations in which an electron is moving in an electric or magnetic field. In which case is the de Broglie wavelength of the electron increasing?

$A$ proton moving with one-tenth of the velocity of light has a certain de Broglie wavelength of $\lambda$. An alpha particle having a certain kinetic energy has the same de Broglie wavelength $\lambda$. The ratio of the kinetic energy of the proton to that of the alpha particle is:

If the momentum of an electron changes by $P$,then the de-Broglie wavelength associated with it changes by $5 \%$. The initial momentum of the electron is: (in $P$)

An electron beam used in an electron microscope,when accelerated by a voltage of $20\,kV$,has a de-Broglie wavelength of $\lambda_0$. If the voltage is increased to $40\,kV$,then the de-Broglie wavelength associated with the electron beam would be:

The de Broglie wavelength of a charged particle accelerated through a potential difference $V$ is $\lambda$. If the potential difference is increased by $21 \%$,the de Broglie wavelength of the charged particle is