For preparing a buffer solution of pH = 6 by | vedclass

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Question

(B) The Henderson-Hasselbalch equation for an acidic buffer is given by: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$Given: $pH = 6$ and $K_a = 10^{-5}$.F

Vedclass · Accepted Answer

$10 : 1$

Vedclass · Answer

(B) The Henderson-Hasselbalch equation for an acidic buffer is given by: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$Given: $pH = 6$ and $K_a = 10^{-5}$.First,calculate $pK_a$: $pK_a = -\log K_a = -\log(10^{-5}) = 5$.Substitute the values into the equation: $6 = 5 + \log \frac{[Salt]}{[Acid]}$.Rearranging gives: $\log \frac{[Salt]}{[Acid]} = 6 - 5 = 1$.Taking the antilog on both sides: $\frac{[Salt]}{[Acid]} = 10^1 = 10$.Therefore,the ratio of the concentration of salt to acid is $10 : 1$.

For preparing a buffer solution of $pH = 6$ by mixing sodium acetate and acetic acid,the ratio of the concentration of salt and acid should be $(K_a = 10^{-5})$

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