For some given data,if M + bar{x} = 32 and M | vedclass

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(D) Given equations are:$M + \bar{x} = 32$  --- $(1)$$M - \bar{x} = 2$  --- $(2)$Adding equation $(1)$ and $(2)$:$(M + \bar{x}) + (M - \bar{x}) = 32 +

Vedclass · Accepted Answer

$21$

Vedclass · Answer

(D) Given equations are:$M + \bar{x} = 32$  --- $(1)$$M - \bar{x} = 2$  --- $(2)$Adding equation $(1)$ and $(2)$:$(M + \bar{x}) + (M - \bar{x}) = 32 + 2$$2M = 34$$M = 17$Substituting $M = 17$ in equation $(1)$:$17 + \bar{x} = 32$$\bar{x} = 32 - 17 = 15$Using the empirical relationship between Mean,Median,and Mode:$Z = 3M - 2\bar{x}$Substituting the values of $M$ and $\bar{x}$:$Z = 3(17) - 2(15)$$Z = 51 - 30$$Z = 21$Therefore,the value of $Z$ is $21$.

Class	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$	$30-35$
Frequency	$11$	$20$	$35$	$20$	$8$	$6$

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$	$90-100$
Frequency	$5$	$7$	$12$	$10$	$8$	$6$	$2$

Age (in years)	$5$-$15$	$15$-$25$	$25$-$35$	$35$-$45$	$45$-$55$	$55$-$65$
Number of patients	$6$	$11$	$21$	$23$	$14$	$5$

For some given data,if $M + \bar{x} = 32$ and $M - \bar{x} = 2$,then $Z = \ldots \ldots \ldots$

Similar Questions

Find the mean,median and mode of the following frequency distribution:

Class $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ $30-35$

Frequency $11$ $20$ $35$ $20$ $8$ $6$

$Z - \bar{x} = \dots \times (M - \bar{x})$

Find the mean,median and mode of the following frequency distribution:

Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$ $90-100$

Frequency $5$ $7$ $12$ $10$ $8$ $6$ $2$

$\frac{Z-M}{M-\bar{x}}=\ldots \ldots \ldots \ldots$

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