For the equation cos^{-1} x + cos^{-1} 2x + p | vedclass

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(C) Given equation: $\cos^{-1} x + \cos^{-1} 2x + \pi = 0$$\Rightarrow \cos^{-1} x + \cos^{-1} 2x = -\pi$Since the range of $\cos^{-1} 	heta$ is $[0,

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$0$

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(C) Given equation: $\cos^{-1} x + \cos^{-1} 2x + \pi = 0$$\Rightarrow \cos^{-1} x + \cos^{-1} 2x = -\pi$Since the range of $\cos^{-1} 	heta$ is $[0, \pi]$,the minimum value of $\cos^{-1} x + \cos^{-1} 2x$ is $0 + 0 = 0$.However,the equation requires the sum to be $-\pi$.Since the sum of two non-negative values cannot be negative,there is no real value of $x$ that satisfies this equation.Therefore,the number of real solutions is $0$.

For the equation $\cos^{-1} x + \cos^{-1} 2x + \pi = 0$,the number of real solutions is:

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