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(D) For a body to be in equilibrium on an inclined plane, the component of gravitational force acting down the plane must be balanced by the static fr

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greater than or equal to one

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(D) For a body to be in equilibrium on an inclined plane, the component of gravitational force acting down the plane must be balanced by the static frictional force.The force acting down the plane is $F_g = mg \sin 	heta$.The maximum static frictional force is $f_{s,max} = \mu_s N$, where $N = mg \cos 	heta$ is the normal force.For equilibrium, the condition is $mg \sin 	heta \leq \mu_s mg \cos 	heta$.This simplifies to $\mu_s \geq 	an 	heta$.Given the inclination $	heta = 45^{\circ}$, we have $\mu_s \geq 	an 45^{\circ}$.Since $	an 45^{\circ} = 1$, the condition becomes $\mu_s \geq 1$.

For the equilibrium of a body on an inclined plane of inclination $45^{\circ}$, the coefficient of static friction must be:

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