For the finite A.P. 5, 9, 13, ldots, 101,find | vedclass

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(B) The given $A.P.$ is $5, 9, 13, \ldots, 101$.Here,the first term $a = 5$ and the common difference $d = 9 - 5 = 4$.The last term $l = 101$.To find

Vedclass · Accepted Answer

$69$

Vedclass · Answer

(B) The given $A.P.$ is $5, 9, 13, \ldots, 101$.Here,the first term $a = 5$ and the common difference $d = 9 - 5 = 4$.The last term $l = 101$.To find the $n^{th}$ term from the end,the formula is $l - (n - 1)d$.Here,$n = 9$,$l = 101$,and $d = 4$.Substituting these values: $101 - (9 - 1) 	imes 4 = 101 - 8 	imes 4 = 101 - 32 = 69$.Therefore,the $9^{th}$ term from the end is $69$.

For the finite $A.P.$ $5, 9, 13, \ldots, 101$,find the $9^{th}$ term from the end.

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