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(D) The molecule $x$ is $N$-phenylbenzamide. It contains two phenyl rings attached to an amide group $(-CONH-)$.In the ring attached to the nitrogen a

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Predominantly at $u$

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(D) The molecule $x$ is $N$-phenylbenzamide. It contains two phenyl rings attached to an amide group $(-CONH-)$.In the ring attached to the nitrogen atom, the lone pair on the nitrogen atom is in conjugation with the benzene ring, making it an activating group. This group is ortho/para directing.In the ring attached to the carbonyl carbon, the carbonyl group $(-C=O)$ is a deactivating group and is meta-directing.Therefore, the electrophilic aromatic substitution will occur on the ring attached to the nitrogen atom. The ortho and para positions relative to the nitrogen atom are the most electron-rich sites.In the given structure, $u$ represents the para position and $s$ represents the ortho position relative to the nitrogen atom. Due to the significant steric hindrance at the ortho position $(s)$ caused by the bulky benzamide group, the electrophile will preferentially attack at the para position $(u)$.

For the given molecule, $x$, the preferred site for the attack of the electrophile is:

Similar Questions

Which of the following is the correct order of reactivity for:

Which of the following orders is correct?

The major product of the above reaction is:

The order of decreasing reactivity in electrophilic addition of the following compounds is
$(I) \, Ph-CH=CH-COOH$
$(II) \, p-NO_2-C_6H_4-CH=CH-COOH$
$(III) \, p-MeO-C_6H_4-CH=CH-COOH$
$(IV) \, p-Cl-C_6H_4-CH=CH-COOH$

Consider the above reaction,the major product $P$ formed is:

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