For the motion on a straight line path with c | vedclass

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Question

(B) For any motion,the distance covered is always greater than or equal to the magnitude of the displacement.Mathematically,$	ext{Distance} \geq |	e

Vedclass · Accepted Answer

$\leq 1$

Vedclass · Answer

(B) For any motion,the distance covered is always greater than or equal to the magnitude of the displacement.Mathematically,$	ext{Distance} \geq |	ext{Displacement}|$.Therefore,the ratio of the magnitude of the displacement to the distance covered is $\frac{|	ext{Displacement}|}{	ext{Distance}} \leq 1$.In a straight-line path,if the motion is unidirectional (no turning back),the distance is equal to the magnitude of the displacement,so the ratio is $1$.If the motion involves a change in direction,the distance will be greater than the magnitude of the displacement,making the ratio less than $1$.Thus,the ratio is always less than or equal to $1$.

For the motion on a straight line path with constant acceleration,the ratio of the magnitude of the displacement to the distance covered is

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