For the propagation of 10 MHz signals as sky | vedclass

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(A) The critical frequency $f_c$ is related to the maximum electron density $N_{max}$ by the formula: $f_c = 9 \sqrt{N_{max}}$.Squaring both sides,we

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$ \sim 1.2 	imes 10^{12} \ m^{-3}$

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(A) The critical frequency $f_c$ is related to the maximum electron density $N_{max}$ by the formula: $f_c = 9 \sqrt{N_{max}}$.Squaring both sides,we get $f_c^2 = 81 	imes N_{max}$.Therefore,$N_{max} = \frac{f_c^2}{81}$.Given $f_c = 10 \ MHz = 10 	imes 10^6 \ Hz = 10^7 \ Hz$.Substituting the value: $N_{max} = \frac{(10^7)^2}{81} = \frac{10^{14}}{81} \approx 1.23 	imes 10^{12} \ m^{-3}$.

For the propagation of $10 \ MHz$ signals as sky waves,what should be the minimum electron density in the ionosphere?

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