(A) For the reaction $A \rightleftharpoons n B$ at equilibrium: Initial concentration of $A = 0.06 \ mol \ L^{-1}$,$B = 0 \ mol \ L^{-1}$. Equilibrium

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(A) For the reaction $A \rightleftharpoons n B$ at equilibrium: Initial concentration of $A = 0.06 \ mol \ L^{-1}$,$B = 0 \ mol \ L^{-1}$. Equilibrium concentration of $A = 0.03 \ mol \ L^{-1}$,$B = 0.06 \ mol \ L^{-1}$. Change in concentration of $A = 0.06 - 0.03 = 0.03 \ mol \ L^{-1}$. Change in concentration of $B = 0.06 - 0 = 0.06 \ mol \ L^{-1}$. According to stoichiometry,$n = \frac{\Delta [B]}{\Delta [A]} = \frac{0.06}{0.03} = 2$. The reaction is $A \rightleftharpoons 2 B$. Equilibrium constant $K_c = \frac{[B]^2}{[A]} = \frac{(0.06)^2}{0.03} = \frac{0.0036}{0.03} = 0.12$.

Class 11 Chemistry 1 Equilibrium: Chemical Equilibrium Mix Examples- 6-1.Equilibrium (Chemical Equilibrium)

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For the reaction,$A \rightleftharpoons n B$,the concentration of $A$ decreases from $0.06 \ mol \ L^{-1}$ to $0.03 \ mol \ L^{-1}$ and that of $B$ rises from $0$ to $0.06 \ mol \ L^{-1}$ at equilibrium. The values of $n$ and the equilibrium constant for the reaction,respectively,are

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$2$ and $0.12$
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$2$ and $1.2$
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$3$ and $0.12$
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$3$ and $1.2$

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For the reaction,$A \rightleftharpoons n B$,the concentration of $A$ decreases from $0.06 \ mol \ L^{-1}$ to $0.03 \ mol \ L^{-1}$ and that of $B$ rises from $0$ to $0.06 \ mol \ L^{-1}$ at equilibrium. The values of $n$ and the equilibrium constant for the reaction,respectively,are

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For the reaction $2P_{(g)} + Q_{(g)} \rightleftharpoons R_{(g)} + S_{(g)}$; $K_C = 10^{12}$. If the initial moles of $P, Q, R, S$ are $2, 1, 7$ and $3$ moles respectively in a $1 \ L$ vessel,find the equilibrium concentration of $P$.

For a reaction taking place in a container in equilibrium with its surroundings,the effect of temperature on its equilibrium constant $K$ in terms of change in entropy is described by:

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Two solids dissociate as follows:$A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$; $K_{p_1} = x \, atm^2$$D_{(s)} \rightleftharpoons C_{(g)} + E_{(g)}$; $K_{p_2} = y \, atm^2$The total pressure when both the solids dissociate simultaneously is:

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Two solids dissociate as follows:
$A_{(s)} \rightleftharpoons B_{(g)} + C_{(g)}$; $K_{p_1} = x \, atm^2$
$D_{(s)} \rightleftharpoons C_{(g)} + E_{(g)}$; $K_{p_2} = y \, atm^2$
The total pressure when both the solids dissociate simultaneously is: