For the reaction CH_3-CH=CH_2 + HOCl to A,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The addition of $HOCl$ to propene follows Markovnikov's rule.$HOCl$ dissociates as $HO^{\delta-} - Cl^{\delta+}$.The electrophile $Cl^{+}$ attacks

Vedclass · Accepted Answer

$CH_3-CH(OH)-CH_2Cl$

Vedclass · Answer

(B) The addition of $HOCl$ to propene follows Markovnikov's rule.$HOCl$ dissociates as $HO^{\delta-} - Cl^{\delta+}$.The electrophile $Cl^{+}$ attacks the double bond to form a cyclic chloronium ion intermediate.The nucleophile $OH^{-}$ then attacks the more substituted carbon atom $(C-2)$ to open the ring.Thus,the reaction is: $CH_3-CH=CH_2 + HOCl 	o CH_3-CH(OH)-CH_2Cl$.Therefore,Option $B$ is the correct answer.

For the reaction $CH_3-CH=CH_2 + HOCl \to A$,the product $A$ is:

Similar Questions

One mole of alkene $\underline{X}$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The $IUPAC$ name of $\underline{X}$ is

The major products of the following reaction are :

Which of the following alkenes is the most stable?

Major product of the given reaction is $CH_2=CH-CH_2-I \xrightarrow[CCl_4]{HI(excess)}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module