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(D) The reaction proceeds in two steps:$1$. Dehydrohalogenation (or elimination of the leaving group) using $KO^tBu$ (a bulky base) and $\Delta$ (heat

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$(CH_3)_2C=O + CH_3COOH$

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(D) The reaction proceeds in two steps:$1$. Dehydrohalogenation (or elimination of the leaving group) using $KO^tBu$ (a bulky base) and $\Delta$ (heat) follows the $E2$ mechanism to form the most stable alkene (Hofmann product is not favored here as the substrate allows for the formation of the more substituted alkene).Starting material: $CH_3-CH(CH_3)-CH(OSO_2CH_3)-CH_3$.Elimination of $OSO_2CH_3$ and a proton from the adjacent carbon leads to the formation of $CH_3-CH(CH_3)-CH=CH_2$ ($3$-methylbut$-1-$ene) or $CH_3-CH(CH_3)-CH=CH-CH_3$ ($2$-methylbut$-2-$ene). The more substituted alkene,$CH_3-C(CH_3)=CH-CH_3$ ($2$-methylbut$-2-$ene),is the major product.$2$. Ozonolysis $(O_3/H_2O_2)$ of $CH_3-C(CH_3)=CH-CH_3$ leads to oxidative cleavage.$CH_3-C(CH_3)=CH-CH_3 \xrightarrow{O_3/H_2O_2} (CH_3)_2C=O + CH_3COOH$.Thus,the major products are acetone and acetic acid.

The major products of the following reaction are :

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