For the resultant of two vectors A and B to b | vedclass

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(B) We know that the magnitude of the resultant $R$ of two vectors $A$ and $B$ is given by the formula:$R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$Here,$R

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$0$

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(B) We know that the magnitude of the resultant $R$ of two vectors $A$ and $B$ is given by the formula:$R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$Here,$R$ is maximum when $\cos 	heta$ is maximum.The maximum value of $\cos 	heta$ is $1$,which occurs when $	heta = 0^{\circ}$.Substituting $	heta = 0^{\circ}$ into the formula:$R_{\max} = \sqrt{A^2 + B^2 + 2AB(1)} = \sqrt{(A+B)^2} = A + B$.Therefore,the resultant is maximum when the angle between the two vectors is $0^{\circ}$.

Column $I$	Column $II$
$(A)$ Component along $x$-axis	$(p)$ $5 \text{ unit}$
$(B)$ Component along vector $(2 \hat{i} + \hat{j} + 2 \hat{k})$	$(q)$ $4 \text{ unit}$
$(C)$ Component along $(6 \hat{i} + 8 \hat{j} - 10 \hat{k})$	$(r)$ $0$
$(D)$ Component along $(-3 \hat{i} - 4 \hat{j} + 5 \hat{k})$	$(s)$ None

For the resultant of two vectors $A$ and $B$ to be maximum,the angle between them should be (in $^{\circ}$)

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