For three circuit elements A, B and C,followi | vedclass

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(B) $1$. Element $A$: $A$ capacitor acts as an open circuit for $DC$ (steady state) because its reactance $X_C = 1/(\omega C)$ is infinite at $f = 0$.

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Capacitor,diode,$	ext{LED}$

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(B) $1$. Element $A$: $A$ capacitor acts as an open circuit for $DC$ (steady state) because its reactance $X_C = 1/(\omega C)$ is infinite at $f = 0$. However,it allows $AC$ to pass through it due to its finite reactance at non-zero frequencies.$2$. Element $B$: $A$ diode (specifically a $p-n$ junction diode) allows current to flow only in one direction (forward bias) for both $AC$ and $DC$ signals.$3$. Element $C$: $A$ Light Emitting Diode $(	ext{LED})$ is a $p-n$ junction diode that emits light when forward-biased. The intensity of light increases with current (voltage) up to a certain point,after which it may decrease or saturate due to thermal effects or device limitations.Therefore,$A$ is a capacitor,$B$ is a diode,and $C$ is an $	ext{LED}$.

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