A particle moves with constant speed v along | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a particle moving in a circular path with constant speed $v$,the acceleration is the centripetal acceleration,given by $a = v^2/r$.Since the p

Vedclass · Accepted Answer

$2\pi v/T$

Vedclass · Answer

(A) For a particle moving in a circular path with constant speed $v$,the acceleration is the centripetal acceleration,given by $a = v^2/r$.Since the particle completes one circle of circumference $2\pi r$ in time $T$,the speed is $v = (2\pi r)/T$.From this,we can write $r = (vT)/(2\pi)$.Substituting the value of $r$ into the acceleration formula: $a = v^2 / ((vT)/(2\pi)) = v^2 \cdot (2\pi) / (vT) = (2\pi v)/T$.Therefore,the acceleration of the particle is $(2\pi v)/T$.

$A$ particle moves with constant speed $v$ along a circular path of radius $r$ and completes the circle in time $T$. The acceleration of the particle is

Similar Questions

$A$ particle is moving along a circular path with constant speed and centripetal acceleration '$a$'. If the speed is doubled,the ratio of its acceleration after and before the change is:

For a particle moving in a circular path with constant speed,which component of its linear acceleration is constant and which component is not constant?

The ratio of the angular velocity of the hour hand of a watch to the angular velocity of the rotation of the Earth is:

In uniform circular motion,

$A$ wheel of radius $30 \ cm$ rotates about its axis and undergoes an angular displacement of $30^\circ$. The linear distance covered by the wheel is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module