Four bells toll at intervals of 8,12,15,and 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find when the bells toll together,we need to calculate the Least Common Multiple $(LCM)$ of $8$,$12$,$15$,and $18$.Prime factorization:$8 = 2^3

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) To find when the bells toll together,we need to calculate the Least Common Multiple $(LCM)$ of $8$,$12$,$15$,and $18$.Prime factorization:$8 = 2^3$$12 = 2^2 	imes 3$$15 = 3 	imes 5$$18 = 2 	imes 3^2$$LCM = 2^3 	imes 3^2 	imes 5 = 8 	imes 9 	imes 5 = 360$ seconds.This means the bells toll together every $360$ seconds,which is $360 / 60 = 6$ minutes.In one hour ($60$ minutes),the number of times they toll together is $60 / 6 = 10$ times.Since we exclude the toll at the start,the total count remains $10$.

Four bells toll at intervals of $8$,$12$,$15$,and $18$ seconds respectively. All four begin to toll together. How many times will they toll together in one hour,excluding the one at the start?

Similar Questions

Find the $LCM$ and $HCF$ of $6$ and $20$ by the prime factorisation method.

The $HCF$ of $25$ and $52$ is $1$.

If two positive integers $a$ and $b$ are written as $a = x^3 y^2$ and $b = x y^3$,where $x$ and $y$ are prime numbers,then $HCF(a, b)$ is:

Find the $LCM$ and $HCF$ of the following pairs of integers and verify that $LCM \times HCF =$ product of the two numbers $26$ and $91$.

The $\text{g.c.d.}$ (greatest common divisor) of any two consecutive natural numbers is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module