From $3n$ consecutive integers, three integers are selected at random. The probability that their sum is divisible by $3$ is

  • A
    $\frac{3^n C_3+n^2}{3^n C_3}$
  • B
    $\frac{2^n C_3+n^3}{3^n C_3}$
  • C
    $\frac{3n^2-3n+2}{(3n-1)(3n-2)}$
  • D
    $\frac{3n^2-3n+2}{(3n+1)(3n+2)}$

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