From an airport,two planes begin their journe | vedclass

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Question

(A) Let the airport be at the origin $(0, 0)$.After $t = 1.5 \, 	ext{hours}$,the distance covered by the first plane moving North is $d_1 = 800 	ime

Vedclass · Accepted Answer

$1740$

Vedclass · Answer

(A) Let the airport be at the origin $(0, 0)$.After $t = 1.5 \, 	ext{hours}$,the distance covered by the first plane moving North is $d_1 = 800 	imes 1.5 = 1200 \, km$.The distance covered by the second plane moving East is $d_2 = 840 	imes 1.5 = 1260 \, km$.Since North and East directions are perpendicular,the distance between the two planes forms the hypotenuse of a right-angled triangle.Using the Pythagorean theorem,the distance $D = \sqrt{d_1^2 + d_2^2}$.$D = \sqrt{1200^2 + 1260^2} = \sqrt{1440000 + 1587600} = \sqrt{3027600}$.$D = 1740 \, km$.

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