From the following masses,the one which is ex | vedclass

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(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mas

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$16.428$

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(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mass nearest to the milligram,the value must be measured up to three decimal places (i.e.,the thousandths place in grams).Comparing the options:$16 \ g$ has $0$ decimal places.$16.4 \ g$ has $1$ decimal place.$16.428 \ g$ has $3$ decimal places,which corresponds to the milligram precision $(16428 \ mg)$.$16.4284 \ g$ has $4$ decimal places,which is more precise than the milligram level.Therefore,$16.428 \ g$ is the value expressed nearest to the milligram.

Prefixes	Multiples
$i$. micro	$10^6$
$ii$. deca	$10^9$
$iii$. mega	$10^{-6}$
$iv$. giga	$10^{15}$
$v$. femto	$10$

From the following masses,the one which is expressed nearest to the milligram is (in $g$)

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Match the following prefixes with their multiples:

Prefixes Multiples

$i$. micro $10^6$

$ii$. deca $10^9$

$iii$. mega $10^{-6}$

$iv$. giga $10^{15}$

$v$. femto $10$

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