From the following options,the line nearest to the origin is ....

  • A
    $3x - 4y + 4 = 0$
  • B
    $2x - 3y - 5 = 0$
  • C
    $4x - 3y + 12 = 0$
  • D
    $5x - 2y - 3 = 0$

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The perpendicular distance from the point $(1, \pi)$ to the line joining $(1, 0^{\circ})$ and $(1, \frac{\pi}{2})$ (in polar coordinates) is

If $(\lambda^2, \lambda+1), \lambda \in \mathbb{Z}$ belongs to the region between the lines $x+2y-5=0$ and $3x-y+1=0$ which includes the origin,then the possible number of such points is

The distance of point $(-2, 3)$ from the line $x - y - 5 = 0$ is

Let $d$ be the distance between the parallel lines $3x - 2y + 5 = 0$ and $3x - 2y + 5 + 2\sqrt{13} = 0$. Let $L_1 \equiv 3x - 2y + k_1 = 0$ $(k_1 > 0)$ and $L_2 \equiv 3x - 2y + k_2 = 0$ $(k_2 > 0)$ be two lines that are at a distance of $\frac{4d}{\sqrt{13}}$ and $\frac{3d}{\sqrt{13}}$ from the line $3x - 2y + 5 = 0$,respectively. Then the combined equation of the lines $L_1 = 0$ and $L_2 = 0$ is:

The length of the perpendicular drawn from the origin upon the straight line $\frac{x}{3} - \frac{y}{4} = 1$ is

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