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(C) The current gain $\beta$ is defined as the slope of the $I_C$ versus $I_B$ graph: $\beta = \frac{\Delta I_C}{\Delta I_B}$.From the graph,taking tw

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$3$

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(C) The current gain $\beta$ is defined as the slope of the $I_C$ versus $I_B$ graph: $\beta = \frac{\Delta I_C}{\Delta I_B}$.From the graph,taking two points $(100\,\mu A, 10\,mA)$ and $(200\,\mu A, 20\,mA)$:$\beta = \frac{(20 - 10) 	imes 10^{-3} \, A}{(200 - 100) 	imes 10^{-6} \, A} = \frac{10 	imes 10^{-3}}{100 	imes 10^{-6}} = 100$.The power gain $A_P$ is given by $A_P = \beta^2 	imes \frac{R_C}{R_B}$.Substituting the values: $A_P = (100)^2 	imes \frac{1 	imes 10^3 \, \Omega}{10 	imes 10^3 \, \Omega} = 10000 	imes 0.1 = 1000 = 10^3$.Comparing this with $10^x$,we get $x = 3$.

From the given transfer characteristic of a transistor in $CE$ configuration,the value of power gain of this configuration is $10^x$,for $R_B = 10\,k\Omega$ and $R_C = 1\,k\Omega$. The value of $x$ is $.....$.

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