From the point $(-1, -6)$, two tangents are drawn to the parabola $y^2 = 4x$. The angle between the two tangents is:
- A$\pi / 3$
- B$\pi / 4$
- C$\pi / 6$
- D$\pi / 2$
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Similar Questions
The angle between the tangents drawn at the end points of the latus rectum of the parabola $y^2 = 4ax$ is
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View SolutionIf the chord joining the points $(at_1^2, 2at_1)$ and $(at_2^2, 2at_2)$ of the parabola $y^2 = 4ax$ passes through the focus of the parabola,then
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View SolutionLet $P$ be the point $(1, 0)$ and $Q$ be a point on the parabola $y^2 = 8x$. Find the locus of the midpoint of $PQ$.
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View SolutionThe equation of the latus rectum of the parabola $x^2 + 4x + 2y = 0$ is:
Medium
View SolutionMatch the items given in List-$A$ with those of the items of List-$B$:
List-$A$ List-$B$ $(A)$. The vertex of the parabola $y^2+4x-2y+3=0$ is $(I)$. $\left(\frac{5}{4}, 1\right)$ $(B)$. The vertex of the parabola $x^2+8x+12y+4=0$ is $(II)$. $\left(1, \frac{5}{4}\right)$ $(C)$. The focus of the parabola $y^2-x-2y+2=0$ is $(III)$. $\left(-\frac{1}{2}, 1\right)$ $(D)$. The focus of the parabola $x^2-2x-8y-23=0$ is $(IV)$. $(1, -1)$ $(V)$. $(-4, 1)$
The correct match is:
| List-$A$ | List-$B$ |
| $(A)$. The vertex of the parabola $y^2+4x-2y+3=0$ is | $(I)$. $\left(\frac{5}{4}, 1\right)$ |
| $(B)$. The vertex of the parabola $x^2+8x+12y+4=0$ is | $(II)$. $\left(1, \frac{5}{4}\right)$ |
| $(C)$. The focus of the parabola $y^2-x-2y+2=0$ is | $(III)$. $\left(-\frac{1}{2}, 1\right)$ |
| $(D)$. The focus of the parabola $x^2-2x-8y-23=0$ is | $(IV)$. $(1, -1)$ |
| $(V)$. $(-4, 1)$ |
The correct match is:
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