Geometry of SiO_{4}^{4-} anion is | vedclass

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Question

(A) In $SiO_{4}^{4-}$,the central silicon atom $(Si)$ has $4$ valence electrons. Each of the $4$ oxygen atoms contributes $1$ electron to form $4$ sin

Vedclass · Accepted Answer

tetrahedral

Vedclass · Answer

(A) In $SiO_{4}^{4-}$,the central silicon atom $(Si)$ has $4$ valence electrons. Each of the $4$ oxygen atoms contributes $1$ electron to form $4$ single bonds with $Si$,and carries a negative charge. The total number of electron pairs around the central $Si$ atom is $4$ (all bond pairs). According to $VSEPR$ theory,$4$ bond pairs correspond to $sp^3$ hybridization. Therefore,the geometry of the $SiO_{4}^{4-}$ anion is tetrahedral.

Geometry of $SiO_{4}^{4-}$ anion is

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