Give equations of four lines passing through the point $(3, 5)$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
$A$ linear equation in two variables passing through a point $(x_0, y_0)$ can be represented in the form $a(x - x_0) + b(y - y_0) = 0$.
Given the point $(3, 5)$,we can choose different values for $a$ and $b$ to find various lines:
$1$. For $a=1, b=1$: $(x - 3) + (y - 5) = 0 \implies x + y = 8$.
$2$. For $a=-1, b=1$: $-(x - 3) + (y - 5) = 0 \implies -x + 3 + y - 5 = 0 \implies y - x = 2$.
$3$. For $a=1, b=2$: $(x - 3) + 2(y - 5) = 0 \implies x - 3 + 2y - 10 = 0 \implies x + 2y = 13$.
$4$. For $a=2, b=1$: $2(x - 3) + (y - 5) = 0 \implies 2x - 6 + y - 5 = 0 \implies 2x + y = 11$.

Explore More

Similar Questions

Which of the following is an equation of a line that passes through points $(-2, 0)$ and $(0, 3)$?

$A$ linear equation in two variables has how many solutions?

If $(2,0)$ is a solution of the linear equation $2x + 3y = k,$ then the value of $k$ is

The graph of the equation $0x + 3y = 21$ is perpendicular to which axis?

Check whether $(4, 0)$ is a solution of the equation $x - 2y = 4$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo