Give the reactions of benzoic acid $(C_6H_5COOH)$ with the following:
$(i)$ Sodium metal
$(ii)$ Solution of sodium hydroxide $(NaOH)$
$(iii)$ Solution of sodium bicarbonate $(NaHCO_3)$
$(iv)$ $P_2O_5$ or conc. $H_2SO_4$ $+$ heat
$(v)$ $PCl_5$
$(vi)$ $PCl_3$
$(vii)$ $SOCl_2$
$(viii)$ $NH_3$ $+$ high temperature
$(ix)$ $LiAlH_4$ / ether or $B_2H_6$
$(x)$ Sodalime $(NaOH + CaO)$ $+$ heat
$(xi)$ Conc. $HNO_3$ $+$ conc. $H_2SO_4$ $+$ heat
$(xii)$ $Br_2 + FeBr_3$
$(xiii)$ Oleum $(H_2SO_4 + SO_3)$ $+$ heat

(A) $(i) 2C_6H_5COOH + 2Na \rightarrow 2C_6H_5COO^-Na^+ + H_2 \uparrow$
$(ii) C_6H_5COOH + NaOH \rightarrow C_6H_5COO^-Na^+ + H_2O$
$(iii) C_6H_5COOH + NaHCO_3 \rightarrow C_6H_5COO^-Na^+ + H_2O + CO_2 \uparrow$
$(iv) 2C_6H_5COOH \xrightarrow{P_2O_5/\Delta} (C_6H_5CO)_2O + H_2O$
$(v) C_6H_5COOH + PCl_5 \rightarrow C_6H_5COCl + POCl_3 + HCl$
$(vi) 3C_6H_5COOH + PCl_3 \rightarrow 3C_6H_5COCl + H_3PO_3$
$(vii) C_6H_5COOH + SOCl_2 \rightarrow C_6H_5COCl + SO_2 + HCl$
$(viii) C_6H_5COOH + NH_3 \rightarrow C_6H_5COONH_4 \xrightarrow{\Delta, -H_2O} C_6H_5CONH_2$
$(ix) C_6H_5COOH \xrightarrow{LiAlH_4/\text{ether}} C_6H_5CH_2OH$
$(x) C_6H_5COOH + NaOH/CaO \xrightarrow{\Delta} C_6H_6 + Na_2CO_3$
$(xi) C_6H_5COOH \xrightarrow{\text{conc. } HNO_3/H_2SO_4, \Delta} m\text{-nitrobenzoic acid}$
$(xii) C_6H_5COOH \xrightarrow{Br_2/FeBr_3} m\text{-bromobenzoic acid}$
$(xiii) C_6H_5COOH \xrightarrow{\text{Oleum}, \Delta} m\text{-sulphobenzoic acid}$