Identify the final product of the following r | vedclass

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(C) $1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene.$2$. Bromination of nitrobenzene with $Br_2/FeBr_3$ gives $m$-bromonitrobenzene

Vedclass · Accepted Answer

$4-$bromo$-1-$chloro$-2-$iodobenzene

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(C) $1$. Nitration of benzene with $HNO_3/H_2SO_4$ gives nitrobenzene.$2$. Bromination of nitrobenzene with $Br_2/FeBr_3$ gives $m$-bromonitrobenzene because the $-NO_2$ group is meta-directing.$3$. Reduction of $m$-bromonitrobenzene with $H_2/Pd/C$ gives $m$-bromoaniline.$4$. Chlorination of $m$-bromoaniline with $Cl_2/FeCl_3$ gives $4$-bromo-$2$-chloroaniline. The $-NH_2$ group is strongly ortho/para directing. The para position is sterically hindered by the $-Br$ group at the meta position relative to the amino group, but the ortho position is more accessible.$5$. Diazotization with $NaNO_2/HCl$ at $0-5  ^\circ C$ converts the $-NH_2$ group to a diazonium salt $(-N_2^+Cl^-)$.$6$. Treatment with $KI$ replaces the diazonium group with an iodine atom, resulting in $4$-bromo-$1$-chloro-$2$-iodobenzene.

Identify the final product of the following reaction sequence:

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Which of the following compounds will undergo Friedel-Crafts alkylation with $CH_3Cl$ / anhydrous $AlCl_3$?
$(a)$ Benzoic acid
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$(d)$ Anisole

The products formed in the following reaction sequence are:

The main product of the following reaction will be
$1$-fluoro-$2$-chloro-$4$-nitrobenzene + piperidine $\to$ Product

The product $(A)$ of the following reaction is:

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