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(C) Dipole moment is a vector quantity. In the $cis$-isomer,the bond dipoles of the two $C-CH_3$ bonds are in the same direction,leading to a non-zero

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Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$

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(C) Dipole moment is a vector quantity. In the $cis$-isomer,the bond dipoles of the two $C-CH_3$ bonds are in the same direction,leading to a non-zero net dipole moment.In the $trans$-isomer,the bond dipoles of the two $C-CH_3$ bonds are equal in magnitude and opposite in direction,which cancel each other out,resulting in a net dipole moment of zero.Since the $cis$-isomer has a non-zero dipole moment and the $trans$-isomer has a zero dipole moment,the $cis$-isomer is more polar.Therefore,both Assertion $(A)$ and Reason $(R)$ are true,and $(R)$ is the correct explanation of $(A)$.

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