Given below are two statements: one is labell | vedclass

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(B) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{\ell}{g}},$ where $\ell$ is the length of the pendulum and

Vedclass · Accepted Answer

Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A).$

Vedclass · Answer

(B) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{\ell}{g}},$ where $\ell$ is the length of the pendulum and $g$ is the acceleration due to gravity. From this formula,it is clear that $T \propto \frac{1}{\sqrt{g}},$ which means the time period decreases as $g$ increases and increases as $g$ decreases. At the top of a mountain,the height $h$ from the surface of the Earth is positive,and the acceleration due to gravity is given by $g_h = g_0 \left( \frac{R}{R+h} \right)^2.$ Since $g_h Because $g$ is smaller at the top,the time period $T$ will be larger at the top of the mountain compared to the base. Therefore,both Assertion $(A)$ and Reason $(R)$ are true,and $(R)$ is the correct explanation of $(A).$

Similar Questions

The variation of acceleration due to gravity $g$ with distance $d$ from the centre of the earth is best represented by ($R =$ Earth's radius)

The force of gravity is least at:

The acceleration due to gravity at the pole $(g_p)$ and at the equator $(g_e)$ are related as:

Which of the following statements are true about the acceleration due to gravity,$g$?
$A$. $g$ is greater at the poles.
$B$. The value of $g$ decreases with height.
$C$. The value of $g$ is the same all over the Earth.
$D$. The value of $g$ is maximum at the center of the Earth.

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