Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A):$ $R-I$ undergoes $S_N2$ reaction faster than $R-Cl$.
Reason $(R):$ Iodine is a better leaving group because of its large size.
In the light of the above statements,choose the correct answer from the options given below:

  • A
    Both $A$ and $R$ are true and $R$ is the correct explanation of $A$.
  • B
    Both $A$ and $R$ are true but $R$ is not the correct explanation of $A$.
  • C
    $A$ is true but $R$ is false.
  • D
    $A$ is false but $R$ is true.

Explore More

Similar Questions

The ${S_{N}2}$ reaction of an asymmetric carbon compound always gives:

Which of the following undergoes $S_N1$ reaction at the fastest rate?

Difficult
View Solution

Match the $CH_{3}X$ compounds in Column-$(I)$ with their $C-X$ bond length in Column-$(II)$ and dipole moment in Column-$(III)$.
$(I)$ Compound$(II)$ $C-X$ Bond Length $(pm)$$(III)$ Dipole Moment $(D)$
$(A)$ $H_3C-F$$(i)$ $214$$(1)$ $1.636$
$(B)$ $H_3C-Cl$$(ii)$ $193$$(2)$ $1.830$
$(C)$ $H_3C-Br$$(iii)$ $178$$(3)$ $1.847$
$(D)$ $H_3C-I$$(iv)$ $139$$(4)$ $1.860$

Difficult
View Solution

The major product obtained in the following reaction is $C_2H_5ONa + (CH_3)_3C-Cl \rightarrow$

The major products $X$ and $Y$ respectively from the following reactions are:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo